What is the value of ‘x’ in \(2\sqrt {3x} - 5\sqrt {27x} + \sqrt {108x} = - 21\)?

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SSC CHSL Previous Paper 59 (Held On: 16 March 2018 Shift 2)

Option 3 : 3

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\( \Rightarrow 2\sqrt {3x} - 5\sqrt {27x} + \sqrt {108x} = - 21\)

\( \Rightarrow 2\sqrt {3x} - 15\sqrt {3x} + 6\sqrt {3x} = - 21\)

\( \Rightarrow - 7\sqrt {3x} = - 21\)

\( \Rightarrow \sqrt {3x} = 3\)

Squaring both side, we get

⇒ 3x = 9

∴ x = 3